## Question

Four bad oranges are mixed accidently with 16 good oranges. Find the probability distribution of the number of bad oranges in a draw of oranges.

### Solution

Let X denote the number of bad oranges in draw of 4 oranges drawn from group if 16 good oranges in the group, therefore X can take values 0, 1 and 2

Now,

P(X = 0) = Probability of getting no bad orange

⇒ P(X = 0) = Probability of getting 2 good oranges

P(X = 1) = Probability of getting one bad oranges

Thus, the probability distribution of X is given by

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